# IBPS PO/CLERK | SSC | UPSSSC Quantitative Aptitude Quiz | Latest Pattern

Hello Aspirants!! Welcome to the Online Quantitative Aptitude Section with explanation.

**Here we are providing Number series quiz which**will be useful for all upcoming exams like IBPS PO, IBPS CLERK, LIC Assistant and NABARD. Attempt and analyze your preparation!

### Direction (1-10): What should come in place of the question mark (?) in the following number series?

1) 6 7 28 64 110 ?
216

a) 158

b) 160

c) 164

d) 161

e) none of these

2) 194, 232, 274,
320, ?

a) 430

b) 380

c) 370

d) 350

e) none of these

3) 20, 39, 66, 101, ?

a) 144

b) 140

c) 120

d) 180

e) none of these

4) 987, 587, 331,
187, 123, ?

a) 104

b) 113

c) 107

d) 114

e) None of these

5) 13, 7, 8, 13.5, ?,
75

a) 29

b) 27

c) 31

d) 28

e) none of these

6) 1, 3, 10, 48 ?,
6432

a) 398

b) 391

c) 400

d) 405

e) none of these

7) 11 6 7 12 ? 67.5

a) 29

b) 27

c) 24

d) 26

e) none of these

8) 5, 10, 17, 26, 37,
50 ?

a) 66

b) 65

c) 67

d) 70

e) none of these

9) 5963, ?, 5938,
5913, 5877, 5828

a) 5932

b) 5940

c) 5951

d) 5954

e) None of these

10)
7,10,16,28,52,?,196

a) 100

b) 90

c) 160

d) 150

e) None of these

Solutions -

1) Answer: d)

Logic: 2nd step
Addition changes +20,+15, +10, +5, +0

2) Answer c)

Logic: 194+38 = 232 ;
232+42 = 274 ; 274+46 = 320 ; 320+50 = 370

3) Answer a)

Logic: 20+19=39 ; 39+(19+8)=66 ; 66+(19+8+8)=101
; 101+(19+8+8+8)=144

4) Answer c)

5) Answer: a)

Logic: Difference of:
×0.5+0.5, ×1+1, ×1.5+1.5, ×2+2, ×2.5+2.5

6) Answer: c)

Logic:

1×1+21 = 3

3×2+22 = 10

10×4+23 = 48

48×8+24 = 400

400×16+25 = 6432

7) Answer: d)

Logic: *0.5+0.5,
*1+1, *1.5+1.5, *2+2

8) Answer b)

Logic: 1*2+3=5 ;
2*3+4=10 ; 3*4+5=17 ; 4*5+6=26 ; 5*6+7=37 ; 6*7+8=50 ; 7*8+9 = 65

9) Answer d)

Logic:

5963–(3)

^{2}= (5963 – 9) = 5954
5954 – (4)

^{2}= (5954 – 16) =5938
5938 – (5)

^{2}= (5938 – 25) = 5913
5913 – (6)

^{2}= (5913 – 36) = 5877
5877 – (7)

^{2}= (5877 – 49) = 5828
10) Answer a)

Logic: In this series
the nth term can be given by (previous term + 3*2n-2) We are supposed to find
6th term, which is given as 52+3*24 = 52+48=100

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